Let x=5,5x5^2=125(-5x5)^2=625Thus, 5x^2 is smaller than (-5x)^2. Assuming that x is a natural number, whole number and rational number.Will try to find x if 5xx^2=(-5xx)^2
Please reply so I know if I did it correctly!
Also assuming the number is not 1!
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Wrong calculation,If x=1,5*1^2=5 and (-5*1)^2=25Thus, they are both not the same.Your errors:5x^2=5*(x*x), not (5*x)*(5*x)
No. As 5x^2=25x^2and(-5x^2)=25x^2 as well
No, as 5x^2 is equivalent to (-5x)^2: 5x^2= 5x*5x(-5x)^2= -5x*-5x=5x*5x= -5x*-5xHence,5x*5x= 5x*5x
Jennifer is correct.5x^2 = 5x^2(-5x)^2 = 25x^2 ( note that when negative * negative will give you a positive number.)Thus, (-5x)^2 is greater than 5x^2 . ( note that even if x is a negative number, after x is being square rooted, x will still be a positive number).
Sorry refer to the second post.
It depends. If x is 10 , then 5x10x10=500 But -50x-50=250. If x is 0, then everything is 0. So with the exception that x is 0, then they are the same.
Jennifer is wrong. 5x^2 is the same as (-5x)^2.Lets take x as 1.First equation:5(1)^2=25.Second equation:(-5(1))^2=25.To confirm this lets do another example, lets take x as 5. First equation :5(5)^2=625Second equation:(-5(5))^2=625Therefore, Jennifer is wrong.
Yes, with one exception.5x^2=5*x*x(-5x)^2=(-5)*(-5)*x*x=25*x*xBut if x=05x^2=5*0*0=0(-5x)^2=25*0*0=05x^2 and (-5x)^2 would be equal.