(3x-1)/4km for each road. Since there are four roads, and each of the roads is (3x-1)/4, then the total of the four roads is obviously 3x-1km when you add them up together. Thank you you

Try road 1 to be 0.5x, then road 2 as 1x-1 then road 3 as 1.25x and road 4 for 0.25x These roads are of different lengths and they are measureable, they are not intergers but in decimal places. They all also add up to be 3x-1

2x+x/2+(x/2+5)+1=3x-1 :)

ReplyDeleteChecking: 2x+x/2+(x/2-5)+4=3x-1

DeleteLengths: 2x, x/2, (x/2-5), 4

Did it wrongly, sry.....

DeleteFirstly, x is a natural number, rational number and is a integer.

DeleteMy x must be greater than 0 (No negative)

x can be 1-∞

DeleteRevised: x∈Z R N

DeleteThe length of the 4 roads are: 1/2x, 1/2x, x, x-1....

ReplyDeleteCheck: 1/2x + 1/2x + x + (x-1) = 3x-1

Conditions: The lengths must be positive integers.

DeleteThe length of the 4 roads are: x-10 km, x+4 km, x km, 5 km

ReplyDeleteCheck: (x-10) , (x+4) , x , 5 = 3x - 1

Conditions: x must be 10>

DeleteThe lengths are: (x) km, (0.75x) km, (0.25x) km, (x-1) km

ReplyDeleteCheck: x + 0.75x + 0.25x + (x-1) = (3x-1) km

The conditions are: It cannot be 1 and below

DeleteCheck: (x-1) * If x is 1*

(x-1) = 0 km * That is not possible for a road to be 0 km*

Check: (x-1) * If x is 1.1*

(x-1) = 0.1 km * That is possible for a road to be 0.1 km*

The possible lengths is (3x-1)/4 km for each of the road.

ReplyDeleteCheck: (3x-1)/4 + (3x-1)/4 + (3x-1)/4 + (3x-1)/4 = (3x - 1) km

DeleteThe possible lengths are 1 km, x+3 km,x+6 km, x-11 km.

DeleteCheck: (1+x+3+x+6+x-11) km = (3x-1) km

Conditions:

X cannot be 0, cannot be less than 11.

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ReplyDelete(3x-1)/4km * 4 = 3x-1km

ReplyDeleteThis comment has been removed by the author.

ReplyDeletex km +x km +x-10 km+9 km

ReplyDeleteCheck: x km +x km +x-10 km+9 km=(3x - 1) km.

The lengths are x km, x km x-10 km and 9km

DeleteMy x is greater than 10.

DeleteThis comment has been removed by the author.

ReplyDelete(3x-1)/4km for each road. Since there are four roads, and each of the roads is (3x-1)/4, then the total of the four roads is obviously 3x-1km when you add them up together. Thank you you

ReplyDeleteThe lengths of the roads are: 1 1/4 x km, x-1 km, 2/4 x km, 1/4 x km.

DeleteLet's check with Chun Leong! 1 1/4 x + x-1 +2/4 x, 1/4 x km.

YAY!

Ans : (3x-1)/4km.

ReplyDeletecheck:(3x-1)/4km+(3x-1)/4km+(3x-1)/4km+(3x-1)/4km=(3x-1)km

For (3x-1)/4, x must be 1 or larger.

DeleteThe length of the 4 roads are: (2x-x)km,(3x-2x)km,(7x-6x)km,(7-7+1)km

ReplyDeleteCheck: (2x-x)km + (3x-2x) + (7x - 6x) + (7-7-1)= 3x - 1

x, x-2,x-10,11

ReplyDeleteCheck:x+(x-2)+(x-10)+11=3x-1

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Deletex = >10

DeleteThis comment has been removed by the author.

ReplyDeleteThe possible lengths of the 4 roads are: 1/2x, 1/2x, x, x-1....

ReplyDeleteCheck: 1/2x + 1/2x + x + (x-1) = 3x-1

this is true if the variable is a positive integer

DeleteXD

x km+ x km,+x-7 km,+6 km=3x-1

ReplyDeletethe possible lengths of the 4roads x,x,x+7,6

DeleteThe length of the 4 roads are: (x-1) km, (0.8x) km, (0.2x) km, x km

ReplyDeleteCheck: (x-1) + (0.8x) + (0.2x) + x = 3x - 1

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Deletex>1

Delete(4x - 3x +1 ) km + (7x - 6x -1) km+ (99 x -98x)km + -1km

ReplyDeleteCHECK:(4x - 3x +1 ) km + (7x - 6x -1) km+ (99 x -98x)km + -1km = 3x-1

Possible lengths of the 4 roads : 2 km, x-6 km, x+14 km, x-11km

ReplyDeleteCheck : (2+x-6+x+14+x-11)km = (3x-1)km

Try road 1 to be 0.5x, then road 2 as 1x-1 then road 3 as 1.25x and road 4 for 0.25x

ReplyDeleteThese roads are of different lengths and they are measureable, they are not intergers but in decimal places.

They all also add up to be 3x-1

my x is greater than 1

Deletex km,x km,x-20km,19km

ReplyDeleteThis would only work if x is greater than 20km

(x-1)km,(x-2)km,(x-3)km,5km

ReplyDeleteThe possible length of the four roads can be x km, x+15km, x-17km, 1 km

ReplyDeleteCheck: X km+x+15 km+x-17 km+1 km=3x -1

x has to be greater than one for the lengths of the roads to be possible.

The possible length are: x km + (x-5)km + (x-2)km + 6km

ReplyDeleteCheck : x km + (x-5)km + (x-2)km + 6km= 3x-1

It will only work when x is greater than 5km

DeleteThe possible lengths of the 4 roads are:x+2,x-2,x/2,x/2-1.

ReplyDeleteCheck:x+2+x-2+x/2+x/2-1=3x-1